Webtanx = sinx/cosx cotx = 1/tanx = cosx/sinx secx = 1/cosx cscx. = 1/sinx As you can see, if secx= 1/cosx, then sec²x= (1/cosx)² = 1/cos²x, similarly, -csc²x = - 1/sin²x They are … WebClick here👆to get an answer to your question ️ Differentiate the following function with respect to x. x1 + tanx . Solve Study Textbooks Guides. ... tan x x + cos x . Medium. View solution > Differentiate the following function with respect to x. sin x x 5 − cos x ...
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WebMar 30, 2024 · Misc 25 Find the derivative of the following functions (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers): (x + … WebTMTA Calculus and Advanced Topics Test, 2007, page 8 36. Given that ln(xey) exln(y) find dx dy. Assume x and y are both positive. a) x x x x y y x 2 ln( ) b) dr. schefkind phone number
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WebBy using tanx differentiation we get, d d x (y) = s e c 2 x – 1. Hence, d d x (tan x – x) = s e c 2 x – 1. Example : What is the differentiation of t a n x with respect to x? Solution : Let y = t a n x. d d x (y) = d d x ( t a n x) By using chain rule we get, d d x (y) = 1 2 x s e c 2 x. Hence, d d x ( t a n x) = 1 2 x s e c 2 x. WebFeb 20, 2024 · To prove the derivative of tan x is sec 2 x by the quotient rule of derivatives, we need to follow the below steps. Step 1: Express tan x as the quotient of two functions. Note that we have. tan x = sin x cos x. ∴ d d x ( tan x) = d d x ( sin x cos x) Step 2: Use the above quotient rule of derivatives. WebJan 15, 2024 · dy/dx = x^cosx(-sinxlnx + cosx/x) y = x^cosx Take the natural logarithm of both sides. lny = ln(x^cosx) Use the logarithm law for powers, which states that loga^n = nloga lny = cosxlnx Use the product rule to differentiate the right hand side. d/dx(cosx) = -sinx and d/dx(lnx). 1/y(dy/dx) = -sinx(lnx) + cosx(1/x) 1/y(dy/dx) = -sinxlnx + cosx/x … colonial spanish word for adjutant