WebEXPRESS HCF OF 210 AND 55 AS 210x+55y, where x and y are integers in two different ways Euclid division algorithm, Real numbers. WebHCF (210, 55) = 5. HCF of 210 and 55 by Long Division Method. The divisor that we receive when the remainder becomes 0 after executing long division repeatedly is the HCF of 210 and 55. No further division can be done. Hence, HCF (210, 55) = 5. HCF of 210 and 55 by Listing Common Factors. To calculate the HCF of 210 and 55 by listing out the ...
If the HCF of 210 and 55 is expressible in the form 210 × …
WebIf the HCF of 210 and 55 is expressible in the form of 210x5+55y, find y. CLASS 10 REAL NUMBERSCLASS-10MATHEMATICSREAL NUMBERSIMPORTANT PROBLEM WebUse Euclid's division algorithm to find the HCF of 210 and 55. Medium Solution Verified by Toppr Step 1 : Given integers are 210 and 55 such as 210>55 By Euclid division lemma 210=55×3+45 .......... (i) Step 2 : Since remainder 45 =0. So for divisor 55 and remainder 45 By Euclid division lemma 55=45×1+10 ...... (ii) Remainder =0 takepayments customer support
If the HCF of 210 and 55 is expressible in the form 210*5+55y, …
WebApr 17, 2015 · Let us first find the HCF of 210 and 55. Applying Euclid division lemma on 210 and 55, we get. 210 = 55 × 3 + 45. 55 = 45 × 1 + 10 . 45 = 4 × 10 + 5 . 10 = 5 × 2 + 0 . We observe that the remainder at this stage is zero. So, the last divisor i.e., 5 is the HCF of 210 and 55. ∴ 5 = 210 × 5 + 55y. ⇒ 55y = 5 - 1050 = -1045. ∴ y = -19 HCF of 210 and 55 is the divisor that we get when the remainder becomes 0 after doing long division repeatedly. 1. Step 1: Divide210 (larger number) by 55 (smaller number). 2. Step 2:Since the remainder ≠ 0, we will divide the divisor of step 1 (55) by the remainder (45). 3. Step 3:Repeat this process until the … See more Prime factorization of 210 and 55 is (2 × 3 × 5 × 7) and (5 × 11) respectively. As visible, 210 and 55 have only one common prime factor i.e. 5. … See more WebIf the HCF of 210 and 55 is expressible in the form 210×5+55y, find y. Medium Solution Verified by Toppr Let us first find the HCFof 210 and 55. Applying Euclids division lemma on 210 and 55, we get 210=55×3+45 Since the remainder 45 =0. So, we now apply division lemma on the divisor 55 and the remainder 45 to get 55=45×1+10 twitch facebook connect